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2x+x^2=20.5
We move all terms to the left:
2x+x^2-(20.5)=0
We add all the numbers together, and all the variables
x^2+2x-20.5=0
a = 1; b = 2; c = -20.5;
Δ = b2-4ac
Δ = 22-4·1·(-20.5)
Δ = 86
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(2)-\sqrt{86}}{2*1}=\frac{-2-\sqrt{86}}{2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(2)+\sqrt{86}}{2*1}=\frac{-2+\sqrt{86}}{2} $
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